Problem

The Auction:

North started with 1♠, East overcalled 2♦., South responded 2♠ and West 3♦. North called 3♥ (trial bid inviting to game). East jumped to 5♦. South went higher and declared 5♠.

East led the ♥6.

Both hand combined North/South hold 11 spades. With an even split the ♠K and ♠J will drop.  North is void in diamonds – no losers.  But North has the Kx in clubs, which might mean losing two tricks. Judging by bidding, East probably holds the ♣A. Also the ♥Q is missing; this adds up to three losers.

How can North win 11 tricks?

Dealer: North

Vul: Both

Contract: 5♠ by North